[ATM] Preston's equation

[Peter De Baan]

Now that is simple math without the math or the headage

2 cents
 
> Date: Mon, 23 Feb 2009 19:10:02 +0100
> From: dlwebb at canit.se
> To: atm at atmlist.net
> Subject: Re: [ATM] Preston's equation
> 
> 
> Interesting? In what sense? Who actually needs to know how much
> glass is theoretically removed during polishing? If this is
> somehow relevant, wouldn't it be more practical to weigh the
> optic before and after? Do the users of such math assume C
> and P are actually constant during polishing? Who needs to
> solve this?
> 
> 
> Dominic
> 
> On Sun, 22 Feb 2009, Anthony Stillman wrote:
> 
> > One interesting note, if you integrate both sides with respect to "t", you see that the volume of material removed "h" is a function of the distance traveled.
> >
> > --- On Sat, 2/21/09, Francis J. O'Reilly <foreilly at verizon.net> wrote:
> >
> > > From: Francis J. O'Reilly <foreilly at verizon.net>
> > > Subject: [ATM] Preston's equation
> > > To: atm at atmlist.net
> > > Date: Saturday, February 21, 2009, 6:39 PM
> > > I came across an equation in my travles that accounts for
> > > the rate of removal of optical glass when polishing. Please
> > > excuse the calculus.
> > >
> > > dh/dt=cpv
> > >
> > > Where dh/dt is the rate of removal of glass
> > >
> > > c is Preston's constant for the particular glass and
> > > slurry being used and can be found in various references.
> > >
> > > p is the pressure at the affected area
> > >
> > > v is the velocity of the mirror or lens with respect to the
> > > tool.
> > >
> > > It seems somewhat intuitive, but I found it interesting
> > > nonetheless to see it published.
> > >
> > > Best,
> > >
> > > Francis J. O'Reilly
> > > _______________________________________________
> > > ATM mailing list http://www.atmlist.net/
> > _______________________________________________
> > ATM mailing list http://www.atmlist.net/
> >
> 
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